Example 1
Find a triangle area
- Identify base 12 cm and perpendicular height 7 cm.
- Use A=½bh.
- Calculate ½×12×7.
- Attach square units.
Final answer: 42 cm²
Check: Two copies form a 12×7 parallelogram of area 84 cm².
AC9M7M01 • Year 7 Maths • Measurement • Learn
solve problems involving the area of triangles and parallelograms using established formulas and appropriate units.
We are learning to solve problems involving the area of triangles and parallelograms using established formulas and appropriate units.
Triangle and parallelogram area depends on a chosen base and its perpendicular height, not on an arbitrary sloping side. Area is measured in square units.
A parallelogram has area bh; rearranging or duplicating a triangle shows that its area is half the matching parallelogram, A=½bh.
For composite regions, partition or subtract non-overlapping pieces with compatible dimensions. Verify by using a second decomposition that covers the same region exactly once.
Use these models to connect the mathematical idea to values, diagrams, coordinates, graphs or structure before moving to symbolic calculation.
Follow each example from representation and setup through calculation/reasoning, interpretation and an independent check.
Example 1
Final answer: 42 cm²
Check: Two copies form a 12×7 parallelogram of area 84 cm².
Example 2
Final answer: 68 cm²
Check: Add non-overlapping rectangles 7×8 and 3×4 to get 68 cm².
Example 3
Problem: A parallelogram has base 12 cm and perpendicular height 7 cm. A triangle with base 8 cm and height 5 cm is cut from it. Find the remaining area and state the correct units.
Final answer: Parallelogram area = 84 cm²; triangle area = 20 cm²; remaining area = 64 cm².
Check: This synthesis problem combines the chapter's core representation, calculation and reasoning skills.
Example 4
Problem: A parallelogram and triangle share base 14 cm and height 5 cm. Compare areas.
Final answer: The parallelogram area is 14×5=70 cm² and the triangle area is ½×14×5=35 cm², so their areas compare in the ratio 2:1.
Check: The complete model for “A parallelogram and triangle share base 14 cm and height 5 cm. Compare areas.” shows The parallelogram area is 14×5=70 cm² and the triangle area is ½×14×5=35 cm², so their areas compare in the ratio 2:1.
Common mistake: Sloping side used as height.
Correction: Locate or construct the perpendicular distance.
Common mistake: Triangle factor one-half omitted.
Correction: Two congruent triangles form a parallelogram.
Common mistake: Mixed length units multiplied.
Correction: Convert first.
Attempt each problem before opening Check answer. The set moves from core understanding to application and synthesis.
1. Find the area of a parallelogram with base 9 cm and height 4 cm.
Answer: 36 cm².
Hint: Multiply base by perpendicular height.
Why: Using the method “Multiply base by perpendicular height.” gives 36 cm².
2. Find the area of a triangle with base 10 m and height 6 m.
Answer: 30 m².
Hint: Use one-half times base times height.
Why: Using the method “Use one-half times base times height.” gives 30 m².
3. Which unit measures area when lengths are metres?
Answer: Square metres, m².
Hint: Identify area as a two-dimensional measure, then choose square units.
Why: Using the method “Area is two-dimensional.” gives Square metres, m².
4. A triangle has area 24 cm² and base 8 cm. Find its height.
Answer: 6 cm.
Hint: Use h=2A÷b.
Why: Using the method “Use h=2A÷b.” gives 6 cm.
5. Find the area of a parallelogram with base 7.5 m and height 3 m.
Answer: 22.5 m².
Hint: Use the perpendicular height.
Why: Using the method “Use the perpendicular height.” gives 22.5 m².
6. A 12×9 rectangle loses a 4×3 corner. Find remaining area.
Answer: 96 square units.
Hint: Subtract the cut-out once.
Why: Using the method “Subtract the cut-out once.” gives 96 square units.
7. Why is a 6 cm sloping side not automatically a triangle height?
Answer: A triangle height is the perpendicular distance to the chosen base; a 6 cm sloping side is a valid height only if it meets that base at 90°.
Hint: Look for a right-angle relationship.
Why: The reasoning for “Why is a 6 cm sloping side not automatically a triangle height?” is complete because A triangle height is the perpendicular distance to the chosen base; a 6 cm sloping side is a valid height only if it meets that base at 90°.
8. A triangular garden has area 54 m² and height 9 m. Find its base.
Answer: From 54=½×b×9, multiply by 2 and divide by 9 to get b=108÷9=12 m; checking gives ½×12×9=54 m².
Hint: Rearrange b=2A÷h.
Why: The complete model for “A triangular garden has area 54 m² and height 9 m. Find its base.” shows From 54=½×b×9, multiply by 2 and divide by 9 to get b=108÷9=12 m; checking gives ½×12×9=54 m².
9. A parallelogram and triangle share base 14 cm and height 5 cm. Compare areas.
Answer: The parallelogram area is 14×5=70 cm² and the triangle area is ½×14×5=35 cm², so their areas compare in the ratio 2:1.
Hint: Apply both formulas to the same base-height pair.
Why: The complete model for “A parallelogram and triangle share base 14 cm and height 5 cm. Compare areas.” shows The parallelogram area is 14×5=70 cm² and the triangle area is ½×14×5=35 cm², so their areas compare in the ratio 2:1.
10. A parallelogram has base 12 cm and perpendicular height 7 cm. A triangle with base 8 cm and height 5 cm is cut from it. Find the remaining area and state the correct units.
Answer: Parallelogram area = 84 cm²; triangle area = 20 cm²; remaining area = 64 cm².
Hint: Represent the information first, then calculate, interpret and independently check the result.
Why: This synthesis problem combines the chapter's core representation, calculation and reasoning skills.
Content description: solve problems involving the area of triangles and parallelograms using established formulas and appropriate units.
The Australian Curriculum code above is exact. Victorian Year 7, NSW Stage 4, US Grade 7, England Key Stage 3, New Zealand Level 4 and comparable international curricula contain broadly related learning, but code-to-code equivalence varies by jurisdiction.
The SkillrHub lesson remains the primary learning resource. This optional video reinforces the explanation; you can complete the lesson and practice without watching.
Before you watch:
Math Antics — Review how area is measured and calculated; then use the topic lesson for triangle and parallelogram formulas.
As you watch: How does counting square units lead to an area calculation?
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Try it: Rearrange a drawn parallelogram into a rectangle and explain why the perpendicular height matters.
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Mapped skill: solve problems involving the area of triangles and parallelograms using established formulas and appropriate units
These references identify matching or closely related learning. Curriculum sequence, terminology and depth vary, so teachers should use the mapped skill and lesson difficulty to confirm suitability.
| Region | Curriculum framework | Closest level or code |
|---|---|---|
| Australia | Australian Curriculum v9.0 | AC9M7M01 · Year 7 |
| Victoria | Victorian Curriculum F–10 Version 2.0 — Mathematics | VC2M7M01 · Level 7 |
| New South Wales | NSW Mathematics K–10 Syllabus (2022) | MA4-ARE-C-01 · Stage 4 |
| United States (USA) | Common Core State Standards for Mathematics | Grade 7 |
| Canada (Ontario) | Ontario Curriculum — Mathematics | Grade 7 |
| United Kingdom (England) | National Curriculum in England — Mathematics | Year 8, Key Stage 3 |
| India | NCERT / CBSE — Mathematics | Class 7 |
Australian Curriculum v9.0 is the canonical source for this SkillrHub lesson. Victoria and NSW entries name the closest published state codes or outcomes; international entries are planning references rather than claims of identical curricula.
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Topic reference: AC9M7M01 — Area of Triangles and Parallelograms
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