Year 8 Maths • Measurement • AC9M8M06

Pythagoras’ Theorem — AC9M8M06

In a right-angled triangle, the square of the hypotenuse equals the sum of the squares of the other two sides. Identify the right angle and hypotenuse first, then use the theorem to find or test side lengths in mathematical and practical settings.

Learning goals
  • Identify the hypotenuse in a right-angled triangle.
  • Use a²+b²=c² to find missing side lengths.
  • Test whether three side lengths form a right triangle.
  • Apply the theorem in practical distance and design problems.
Prerequisite knowledge

Recall square numbers, square roots, right angles, triangle side notation, substitution and rearranging a simple equation.

Key concept

The theorem applies only to right-angled triangles. The hypotenuse c is opposite the right angle and is always the longest side. Then a²+b²=c².

To find a shorter side, subtract a known leg-square from the hypotenuse-square before taking the positive square root. To test a triangle, use the largest side as the candidate c and compare a²+b² with c².

Preserve the full AC9 elaboration range: compare historical demonstrations/proofs from several mathematical traditions, solve practical missing-length problems, examine how square relationships differ for acute/right/obtuse triangles, recognise Pythagorean triples, and connect right-triangle distance to coordinate-plane/predictive navigation contexts without drifting into later trigonometry.

Worked examples
abca² + b² = c²c is opposite 90°
The identity is a relationship between side squares, not a rule for arbitrary triangles.

Find a hypotenuse

Legs 6 and 8: c=√(6²+8²)=√100=10.

Find a shorter side

c=13 and one leg=5: b=√(13²−5²)=√144=12.

Test a triple

7,24,25: 7²+24²=49+576=625=25², so it is right-angled.

Coordinate distance

From (2,1) to (8,9), horizontal change=6 and vertical change=8; distance=√(6²+8²)=10 units.

Common misconceptions
  • Choosing any side as c. c must be opposite the right angle and longest.
  • Adding side lengths instead of squares. The theorem relates squared lengths.
  • Using a²+b²=c² for a non-right triangle. The right-angle condition is essential.
  • Keeping both ± square roots for a length. Physical side length uses the positive root.
Guided practice
  1. Label c on three differently oriented right triangles.
  2. Find c for legs 9 and 12.
  3. Find a missing leg when c=17 and the other leg=8.
  4. Test 8,15,17 as a Pythagorean triple.
Independent practice
  1. Find the hypotenuse for legs 5 and 11.
  2. Find a leg when c=20 and the other leg=16.
  3. Test whether 6,8,11 forms a right triangle.
  4. Find the diagonal of a 9 m×12 m rectangle.
  5. Find the straight-line distance between (1,2) and (7,10).
  6. Explain why 3,4,5 and 6,8,10 are related triples.
  7. Describe one historical or practical way to demonstrate the theorem’s relationship.
Reasoning/problem-solving

A builder measures a rectangular frame as 2.4 m by 3.2 m and one diagonal as 4.05 m. The theoretical right-rectangle diagonal is 4.0 m. Explain what the discrepancy could mean, what measurement accuracy matters, and how a second diagonal would help diagnose whether the frame is square.

Questions and answers
  1. How do you identify the hypotenuse? It is opposite the right angle and is the longest side.
  2. When does Pythagoras apply? Only for right-angled triangles.
  3. How do you test a triangle from side lengths? Square the two shorter sides and compare their sum with the square of the longest.
  4. What is a Pythagorean triple? Three integer side lengths satisfying a²+b²=c².
Practice and review
  1. A ladder reaches 4.8 m up a wall and its foot is 2 m from the wall. Find ladder length to 2 decimal places.
    The ladder is the hypotenuse.
  2. A triangle has sides 9,12,15. Determine whether it is right-angled and justify.
    Use 15 as c and compare squares.
  3. Find the distance between A(−2,3) and B(4,11).
    Use horizontal/vertical differences as perpendicular legs.
Check understanding
  • I identify c correctly.
  • I find hypotenuse or leg lengths.
  • I test right-triangle side sets.
  • I apply the theorem to coordinates/practical geometry.

Exit ticket: Why must the longest side be tested as c when checking three lengths?

Teacher + parent guidance

Teacher

Use area-of-squares reasoning before formula substitution. Keep historical demonstrations, triples and coordinate-distance applications so students see the theorem as a relationship, not a calculator routine.

Parent/carer

Use rectangle diagonals, ladders or screen sizes. Ask the student to point to the right angle and hypotenuse before calculating.

Support: begin with labelled right triangles and familiar triples.
Core: mix hypotenuse/leg problems, decimal answers and practical contexts.
Extend: test near-right triangles, coordinate distances or compare multiple demonstrations/proofs without introducing trigonometry.
Curriculum alignment

Australian Curriculum v9.0 — AC9M8M06: use Pythagoras’ theorem to solve problems involving the side lengths of right-angled triangles.

Victorian Curriculum F–10 Version 2.0 — Level 8, VC2M8M06: Exact.

NSW Mathematics K–10 Syllabus (2022) — Stage 4, MA4-PYT-C-01; MAO-WM-01: Exact for applying Pythagoras’ theorem in contexts, supported by Working mathematically.

LessonAC v9VictoriaNSW
Pythagoras’ theoremAC9M8M06VC2M8M06 — ExactMA4-PYT-C-01; MAO-WM-01 — Exact
Practice/teaching resources
Official curriculum references
🎥 Optional Video Lesson

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Recommended: The Pythagorean Theorem

Math Antics — Find a missing side of a right-angled triangle using the relationship between the three squared side lengths.

As you watch: How do you identify the hypotenuse before choosing the calculation?

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Try it: A right-angled triangle has perpendicular sides of 6 cm and 8 cm. Find its hypotenuse and check the squared lengths.

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Curriculum equivalents: Victoria, NSW and international

Curriculum equivalents for Pythagoras’ theorem to solve problems involving the side lengths of...

Mapped skill: use Pythagoras’ theorem to solve problems involving the side lengths of right-angled triangles

These references identify matching or closely related learning. Curriculum sequence, terminology and depth vary, so teachers should use the mapped skill and lesson difficulty to confirm suitability.

RegionCurriculum frameworkClosest level or code
AustraliaAustralian Curriculum v9.0AC9M8M06 · Year 8
VictoriaVictorian Curriculum F–10 Version 2.0 — MathematicsVC2M8M06 · Level 8
New South WalesNSW Mathematics K–10 Syllabus (2022)MA4-PYT-C-01 + MAO-WM-01 · Stage 4
United States (USA)Common Core State Standards for MathematicsGrade 8
Canada (Ontario)Ontario Curriculum — MathematicsGrade 8
United Kingdom (England)National Curriculum in England — MathematicsYear 9, Key Stage 3
IndiaNCERT / CBSE — MathematicsClass 8

Australian Curriculum v9.0 is the canonical source for this SkillrHub lesson. Victoria and NSW entries name the closest published state codes or outcomes; international entries are planning references rather than claims of identical curricula.

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