Example 1 — identify exponential change
For x = 0,1,2,3 the y-values are 6, 18, 54, 162. Each value is multiplied by 3, so the relation is exponential with multiplier 3.
Year 10 Mathematics • Algebra
Exponential change is about multiplication, not simply “a graph that curves”. Learn to recognise constant ratios, read the meaning of y = abˣ, connect tables, rules and graphs, and solve related equations exactly or approximately.
You should know exponent laws, substitution, coordinates and basic graph interpretation. You should also recognise linear relations from a constant first difference. This lesson does not require logarithms; logarithms are a later/Path method for solving more difficult exponential equations.
When x increases by equal steps, an exponential relation multiplies y by the same factor. The values 5, 10, 20, 40 have constant ratio 2. The values 5, 10, 15, 20 have constant difference 5, so they are linear instead.
For y = abˣ, a is the value when x = 0 because b⁰ = 1. The number b is the multiplier for each increase of 1 in x. If b > 1, values grow. If 0 < b < 1, values decay.
A 7% increase means multiply by 1.07, not 0.07. A 7% decrease means retain 93%, so multiply by 0.93. Repeated percentage change is exponential because the percentage is applied to a changing amount.
For a positive a and b, the graph passes through (0,a). In a basic growth model y = abˣ with a>0 and b>1, the curve rises increasingly quickly; for 0<b<1, it falls towards 0. The algebraic multiplier and graphical shape are two representations of the same relationship.
If both sides can be written with the same base, equate exponents. For equations such as 2ˣ = 10, a Year 10 method can use a graph, table or digital solver and report an approximate solution. Do not introduce logarithms as though they are required by this descriptor.
For x = 0,1,2,3 the y-values are 6, 18, 54, 162. Each value is multiplied by 3, so the relation is exponential with multiplier 3.
7, 11, 15, 19 has constant difference +4, so it is linear. 7, 14, 28, 56 has constant ratio 2, so it is exponential.
A sequence starts at 3 when x=0 and doubles each step. Therefore y=3·2ˣ.
For y=120(0.8)ˣ, the initial value is 120. The multiplier 0.8 means 80% remains each step, so there is 20% decay per step.
2ˣ = 32 = 2⁵, therefore x = 5.
3·2ˣ=24 → 2ˣ=8=2³, so x=3.
For y=4·2ˣ, the y-intercept is 4 and the output doubles whenever x increases by 1. A graph passing through (0,4), (1,8), (2,16) displays those same algebraic facts.
To solve 2ˣ=10, compare values: 2³=8 and 2⁴=16, so 3<x<4. A graph or digital solver gives x≈3.322. The approximation should be labelled with ≈.
P=500(1.1)ᵗ. P(7)≈974 and P(8)≈1072, so the model first exceeds 1000 at t=8 whole periods.
P=P₀(1.04)ᵗ models 4% growth per period. It may work over a limited interval, but real populations can face changing resources, habitat and management conditions. A mathematically valid exponential rule is not automatically a permanently valid real-world model.
Two online videos start with 1000 views. Video A gains 600 views per day. Video B grows by 35% per day.
Review hint: When asked to “connect representations”, do not just calculate. Explain how a feature in the table or equation appears on the graph.
Move repeatedly among table, equation, graph and context. The common weakness is procedural recognition without representational connection. Give near-miss tables where differences are constant but ratios are not, and require students to justify classification. Treat logarithmic solving as optional extension aligned to local pathways, not as prerequisite content for this page.
Ask “Is the amount being added each time, or multiplied each time?” That question often separates linear from exponential thinking. When a percentage changes repeatedly, encourage the student to convert it into a multiplier before calculating.
Australian Curriculum: AC9M10A03, Year 10 Algebra — connecting algebraic and graphical representations of exponential relations and solving related exponential equations, using digital tools where appropriate.
Victoria: VC2M10A11, Level 10 Algebra supports connections between algebraic and graphical representations including exponential relations; VC2M10A14 covers simple exponential equations. VC2M10A16 can support numerical/graphical solving with digital tools.
NSW: MA5-NLI-C-01 identifies connections between algebraic and graphical representations of quadratic and exponential relationships; MA5-NLI-C-02 compares features of parabolas and exponential curves. MA5-LOG-P-01 is a supporting advanced Path outcome for logarithmic techniques, but logarithms are not presented here as required Australian Curriculum content.
Alignment explanation: Constant-ratio recognition, parameter interpretation and graph/equation connections directly support the Australian, Victorian and NSW non-linear relationship expectations. Simple equation-solving aligns strongly with Victoria A14; NSW may extend equation solving through advanced Path content, so that extension is clearly separated from the core lesson.
| Lesson component | Australian Curriculum | Victoria | NSW |
|---|---|---|---|
| Recognise exponential patterns | AC9M10A03 | VC2M10A11/A14 supporting | MA5-NLI-C-01 |
| Connect equation and graph | AC9M10A03 | VC2M10A11 | MA5-NLI-C-01, C-02 |
| Solve simple exponential equations | AC9M10A03 | VC2M10A14 | Non-linear content; MA5-LOG-P-01 only for advanced extension |
| Digital/approximate solving | AC9M10A03 | VC2M10A16 supporting | MAO-WM-01 + relevant Path support |
The SkillrHub lesson remains the primary learning resource. This optional video reinforces the explanation; you can complete the lesson and practice without watching.
Before you watch:
Khan Academy — Connecting an exponential expression with its table and graph.
As you watch: What happens to the output when the input increases by one?
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Try it: Make a table and graph of y = 2ˣ for x from -2 to 3; identify where y = 8.
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Mapped skill: recognise the connection between algebraic and graphical representations of exponential relations and solve related exponential equations, using digital tools where appropriate
These references identify matching or closely related learning. Curriculum sequence, terminology and depth vary, so teachers should use the mapped skill and lesson difficulty to confirm suitability.
| Region | Curriculum framework | Closest level or code |
|---|---|---|
| Australia | Australian Curriculum v9.0 | AC9M10A03 · Year 10 |
| Victoria | Victorian Curriculum F–10 Version 2.0 — Mathematics | VC2M10A11 + VC2M10A14 + VC2M10A16 · Level 10 |
| New South Wales | NSW Mathematics K–10 Syllabus (2022) | MA5-LOG-P-01 + MA5-NLI-C-01 + MA5-NLI-C-02 + MAO-WM-01 · Stage 5 |
| United States (USA) | Common Core State Standards for Mathematics | Grades 9–10 band |
| Canada (Ontario) | Ontario Curriculum — Mathematics | Grade 10 |
| United Kingdom (England) | National Curriculum in England — Mathematics | Year 11, Key Stage 4 |
| India | NCERT / CBSE — Mathematics | Class 10 |
Australian Curriculum v9.0 is the canonical source for this SkillrHub lesson. Victoria and NSW entries name the closest published state codes or outcomes; international entries are planning references rather than claims of identical curricula.
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Topic reference: AC9M10A03 — Exponential Relations, Graphs and Equations — AC9M10A03
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